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കണക്ക്‌ : കളിയും കാര്യവും

 

06-03-2014

1.        
ഒരേ നീളമുള്ള 2 ട്രെയിനുകള്‍ സമാന്തര പാതകളിലൂടെ ഒരേ ദിശയിലേക്ക് ആദ്യ ട്രെയിന്‍ 46 km/hr ,രണ്ടാമത്തേത് 36 km/hr  സഞ്ചരിക്കുന്നു .സ്പീഡ് കുറഞ്ഞ ട്രെയിന്‍ സ്പീഡ് കൂടിയ ട്രെയിനിനെ 36 sec കൊണ്ട് മുറിച്ചുകടന്നു പോകുന്നു . എങ്കില്‍ ട്രെയിനിന്റെ നീളം എത്ര ?

 

 

1.    Smart Formulas :  
1. Speed = distance/time

  s = d/t

2.    2. Time taken by a train x meters long to pass a pole or standing man or a post = Time taken by the train to travel x meters.

3.   
3. Time taken by a train x meters long to pass an object of length y meters = Time taken by the train to travel (x + y) metres.

4.    Suppose two trains or two objects are moving in the same direction at v1 m/s and v2 m/s where v1 > v2,

then their relative speed = (v1 – v2) m/s

5.    4. Assume two trains of length x metres and y metres are moving in opposite directions at v1 m/s and v2 m/s, Then

The time taken by the trains to cross each other = (x+y) / (v1+v2) seconds

6.    5. Assume two trains of length x metres and y metres are moving in the same direction at at v1 m/s and v2 m/s where v1 > v2, Then

The time taken by the faster train to cross the slower train = (x+y) / (v1-v2) seconds

 

Smart Answer : 50 mtr
 

Explanation :

Assume the length of each train = x 

Total distance covered for overtaking the slower train = x+x = 2x 

Relative speed = 46-36 = 10km/hr = (10×10)/36 = 100/36 m/s 

Time = 36 seconds 

2x/ (100/36) = 36 

=> (2x × 36 )/100 = 36 

=> x = 50 meter

 
 
 

 

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